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## Three capacitors having capacitances of 8.40, 8.40, and 4.20μF, respectively, are connected in series across a 36.0-V potential difference.

Question

Three capacitors having capacitances of 8.40, 8.40, and 4.20μF, respectively, are connected in series across a 36.0-V potential difference. (a) What is the charge on the 4.20−μF capacitor? (b) The capacitors are disconnected from the potential difference without allowing them to discharge. They are then reconnected in parallel with each other with the positively charged plates connected together. What is the voltage across each capacitor in the parallel combination?

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Physics
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2021-08-30T19:30:23+00:00
2021-08-30T19:30:23+00:00 1 Answers
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## Answers ( )

Answer:Therefore,The charge on the 4.20μF capacitor is 75.6μC.The voltage across each capacitor in the parallel combination is 10.8 Volt.Explanation:Given:

Three capacitors having capacitance,

are connected in series across a 36.0-V potential difference,

V= 36 V

To Find:

Qs = ? charge on the 4.20−μF

V = ? voltage across each capacitor in the parallel combination

Solution:

For Capacitor

SeriesCombination we have,Substituting the values we get

As Capacitors are connected in series they have the

same chargeon each plates, and is given bySubstituting the values we get

Now when the plates are connected in

Parallelwe will have,Substituting the values we get

As Capacitors are connected in Parallel they have the

same Voltageon each plates, and is given bySubstituting the values we get

Therefore,The charge on the 4.20μF capacitor is 75.6μC.The voltage across each capacitor in the parallel combination is 10.8 Volt.