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There are 4.2 moles of an unknown gas at a pressure of 5.5 atm that also have a volume of 12.0 L. What is the temperature of this gas?

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There are 4.2 moles of an unknown gas at a pressure of 5.5 atm that also have a volume of 12.0 L. What is the temperature of this gas?

Question

There are 4.2 moles of an unknown gas at a pressure of 5.5 atm that also have a volume of 12.0 L. What is the temperature of this gas?

## Answers ( )

Answer:

191.4K

Explanation:

Using the ideal gas law equation as follows:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question:

n = 4.2moles

P = 5.5atm

V = 12.0 L

T = ?

Using PV = nRT

5.5 × 12 = 4.2 × 0.0821 × T

66 = 0.345 T

T = 66/0.345

T = 191.4K