the wheel on the tv program wheel of fortune is first divided equally into 24 compartments with one labeled”lose a turn” find the probabilit

Question

the wheel on the tv program wheel of fortune is first divided equally into 24 compartments with one labeled”lose a turn” find the probability that the wheel stops a “lose turn” for each of the following a.single spinb.two successive spins c. three successive spins (complete solution)​

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Thu Nguyệt 6 months 2021-08-08T13:54:45+00:00 1 Answers 0 views 0

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    2021-08-08T13:56:24+00:00

    Answer:

    a) \frac{1}{24} probability that the wheel stops a “lose turn” for a single spin.

    b) \frac{1}{576} probability that the wheel stops a “lose turn” for two successive spins.

    c) \frac{1}{13824} probability that the wheel stops a “lose turn” for three successive spins.

    Step-by-step explanation:

    A probability is the number of desired outcomes divided by the number of total outcomes.

    24 components on the wheel, one of which is “lose a turn”

    This means that each time the wheel stops, there is a \frac{1}{24} probability that it stops at lose a turn.

    a.single spin

    Only one spin, so:

    (\frac{1}{24})^1 = \frac{1}{24}

    \frac{1}{24} probability that the wheel stops a “lose turn” for a single spin.

    b.two successive spins

    Two spins, so:

    (\frac{1}{24})^2 = \frac{1}{576}

    \frac{1}{576} probability that the wheel stops a “lose turn” for two successive spins.

    c. three successive spins

    Three spins, so:

    (\frac{1}{24})^3 = \frac{1}{13824}

    \frac{1}{13824} probability that the wheel stops a “lose turn” for three successive spins.

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