The volume of the vessel is reduced twice,and the number of molecules is reduced three times.How the pressure will change gas?​

Question

The volume of the vessel is reduced twice,and the number of molecules is reduced three times.How the pressure will change gas?​

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Adela 1 year 2021-09-03T23:33:22+00:00 1 Answers 0 views 0

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    2021-09-03T23:34:35+00:00

    Answer:

         P₁ = ⅔ P₀

    Explanation:

    For this exercise we can use the ideal gas equation

             PV = n R T

    let’s write the equation for the initial point, where we will use the subscript o and the end with subscript 2

             

    Suppose the temperature does not change in the process

            P₀V₀ / n₀ = P₁V₁ / n₁

    They tell us that

          V₁ = V₀ / 2

           n₁ = n₀ / 3

     

    we substitute

         [tex]P_o \frac{V_o}{n_o} = P_1 \frac{V_o}{2} \frac{3}{n_o}[/tex]  

            P₀ = [tex]\frac{3}{2}[/tex]     P₁  

            P₁ = ⅔ P₀

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