# The volume of the vessel is reduced twice,and the number of molecules is reduced three times.How the pressure will change gas?​

Question

The volume of the vessel is reduced twice,and the number of molecules is reduced three times.How the pressure will change gas?​

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1 year 2021-09-03T23:33:22+00:00 1 Answers 0 views 0

P₁ = ⅔ P₀

Explanation:

For this exercise we can use the ideal gas equation

PV = n R T

let’s write the equation for the initial point, where we will use the subscript o and the end with subscript 2

Suppose the temperature does not change in the process

P₀V₀ / n₀ = P₁V₁ / n₁

They tell us that

V₁ = V₀ / 2

n₁ = n₀ / 3

we substitute

$$P_o \frac{V_o}{n_o} = P_1 \frac{V_o}{2} \frac{3}{n_o}$$

P₀ = $$\frac{3}{2}$$     P₁

P₁ = ⅔ P₀