The volume of gas decreases at constant temperature to 80% of the inital value. How does the pressure value change relative to the initial v

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The volume of gas decreases at constant temperature to 80% of the inital value. How does the pressure value change relative to the initial value

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Thu Cúc 6 months 2021-07-30T15:21:51+00:00 1 Answers 5 views 0

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    2021-07-30T15:23:28+00:00

    Answer:

    The pressure value changes 400 % relative to the initial value.

    Explanation:

    Let suppose that the gas behaves ideally and represents a closed system, that is, a system with no mass interactions so that number of moles is conserved (n). Since the variables involved in the isothermal process are pressure (P) and volume (V). Finally, the process is represented by the following relationship:

    P_{1}\cdot V_{1} = P_{2}\cdot V_{2} (1)

    Where:

    P_{1}, P_{2} – Initial and final pressures.

    V_{1}, V_{2} – Initial and final volumes.

    If we know that P_{1} = P_{o}, V_{1} = V_{o} and V_{2} = 0.2\cdot V_{o}, then the final pressure of the closed system is:

    P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}} \right)

    P_{2} = 5\cdot P_{o}

    The pressure value changes 400 % relative to the initial value.

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