## The voltage v(t) 5 359.3 cos(vt) volts is applied to a load consisting of a 10- resistor in parallel with a capacitive reactance XC 5 25 Ω.

Question

The voltage v(t) 5 359.3 cos(vt) volts is applied to a load consisting of a 10- resistor in parallel with a capacitive reactance XC 5 25 Ω. Calculate (a) the instantaneous power absorbed by the resistor, (b) the instantaneous power absorbed by the capacitor, (c) the real power absorbed by the resistor, (d) the reactive power delivered by the capacitor, and (e) the load power factor.

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6 months 2021-07-15T22:42:44+00:00 1 Answers 20 views 0

(a). The instantaneous power absorbed by the resistor is (b). The instantaneous power absorbed by the capacitor is (c). The real power absorbed by the resistor is 6454.82 watts.

(d). The real power absorbed by the capacitor is 2581.92 watts.

(e) The load factor is 2.5

Explanation:

Given that,

Voltage Resistor = 10 Ω

Capacitive reactance = 25 Ω

We need to calculate the current by the resistance

Using formula of current Put the value into the formula  We need to calculate the current by the capacitance

Using formula of current Put the value into the formula  (a). We need to calculate the instantaneous power absorbed by the resistor

Using formula of power Put the value into the formula    ….(I)

(b). We need to calculate the instantaneous power absorbed by the capacitor

Using formula of power    ….(II)

(c). We need to find the real power absorbed by the resistor

Using equation (I)

The real power absorbed by the resistor is 6454.82 watts.

(d). We need to find the real power absorbed by the capacitor

Using equation (II)

The real power absorbed by the capacitor is 2581.92 watts.

(e). We need to calculate the load factor Put the value into the formula  Hence, (a). The instantaneous power absorbed by the resistor is (b). The instantaneous power absorbed by the capacitor is (c). The real power absorbed by the resistor is 6454.82 watts.

(d). The real power absorbed by the capacitor is 2581.92 watts.

(e) The load factor is 2.5