The vertical component of a velocity vector points up and has a magnitude of 20, ms’. The velocity vector Itself makes an angle of 25′ with

Question

The vertical component of a velocity vector points up and has a magnitude of 20, ms’. The velocity vector Itself makes an angle of 25′ with the horizontal. Find the magnitude of the velocity vector.

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Linh Đan 6 months 2021-07-26T22:04:19+00:00 1 Answers 13 views 0

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    2021-07-26T22:05:36+00:00

    Answer:

    Kindly check explanation

    Explanation:

    Given the following :

    Vertical component has Magnitude = 20m/s

    Angle made with the horizontal (θ) = 25°

    Vy = Vsinθ = 20sin25

    Vy = 20 × 0.4226182 = 8.4523652 m/s

    Horizontal component :

    Vx = Vcosθ = 20 × cos25

    Vx = 20 × 0.9063077 = 18.126155 m/s

    Hence, magnitude :

    V = sqrt(Vx² + Vy²)

    V = sqrt(8.4523652² + 18.126155²)

    V = sqrt (399.99999)

    V = 20m/s

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