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The velocity of particle varies with time as equation v=3tî – 2tj The acceleration of particle at t= 1 s is
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Answer:
Don’t know if you meant to write 3t²i – 2tj
If so
a=dv/dt = 6ti – 2j
at t=1sec
a = 6(1)I – 2j
a=6i – 2j
Magnitude of a = √6²+(-2)²
a= 2√10ms-²
or 6.32ms-².
Velocity of a particle varies with its displacement as v = ( √(9 … Velocity of a particle varies with its displacement as v = ( √(9 – x^2) ) m/sFind the magnitude of maximum acceleration of the particle.