The tune-up specifications of a car call for the spark plugs to be tightened to a torque of 38N⋅m38N⋅m. You plan to tighten the plugs by pul

Question

The tune-up specifications of a car call for the spark plugs to be tightened to a torque of 38N⋅m38N⋅m. You plan to tighten the plugs by pulling on the end of a 25-cm-long wrench. Because of the cramped space under the hood, you’ll need to put at an angle of 120∘with respect to the wrench shaft. With what force must you pull?

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Dulcie 1 month 2021-08-16T02:29:14+00:00 1 Answers 0 views 0

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    2021-08-16T02:30:53+00:00

    Answer:

    F= 175.5N

    Explanation:

    Given:

    Torque which can also be called moment is defined as rotational equivalent of linear force. It is the product of the external force and perpendicular distance

    torque of 38N⋅m

    angle of 120∘

    Torque(τ): 38Nm

    position r relative to its axis of rotation: 25cm , if we convert to metre for consistency we have 0.25m

    Angle: 120°

    To find the Force, the torque equation will be required which is expressed below

    τ = Frsinθ

    We need to solve for F, if we rearrange the equation, we have the expression below

    F= τ/rsinθ

    Note: the torque is maximum when the angle is 90 degrees

    But θ= 180-120=60

    F= 38/0.25( sin(60) )

    F= 175.5N

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