The time-average power carried by a UPEMW propagating in vacuum is 0.05 W/m2. i) What is the amplitude value of the electric field and the a

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The time-average power carried by a UPEMW propagating in vacuum is 0.05 W/m2. i) What is the amplitude value of the electric field and the amplitude value of the magnetic field in the wave

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Thiên Di 2 months 2021-07-23T11:29:35+00:00 1 Answers 2 views 0

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    2021-07-23T11:30:58+00:00

    Answer:

    The correct solution is “11.51 mA“.

    Explanation:

    Given:

    Time average power,

    P_{avg}=0.05 \ W/m^2

    n = 377

    As we now,

    P_{avg}=\frac{E_0^2}{n}

    or,

    E_0^2=0.05\times 377

    ⇒       =4.341 \ V

    hence,

    H_0=\frac{E_0}{n}

    By putting the values, we get

             =\frac{4.341}{377}

             =11.51 \ mA

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