The temperature of 170 g of a material decreases by 20.0⁰C when it loses 3050 J of heat. What is its specific heat

Question

The temperature of 170 g of a material decreases by 20.0⁰C when it loses 3050 J of heat. What is its specific heat

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Adela 3 years 2021-08-23T15:46:44+00:00 1 Answers 1 views 0

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    2021-08-23T15:48:01+00:00

    Answer:

    0.897 J/g.⁰C

    Explanation:

    Given the following data:

    m = 170 g (mass)

    ΔT = 20.0⁰C (change in temperature)

    q = 3050 J (amount of heat)

    The amount of heat (q) is calculated as follows:

    q = m x Cp x ΔT

    Thus, we introduce the data in the mathematical expression to calculate the specific heat (Cp):

    Cp = q/(m x ΔT) = 3050 J/(170 g x 20.0⁰C) = 0.897 J/g.⁰C

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