The surface areas of two cubes have a ratio of 49to 81. What is the ratio of the edge lengths of the two cubes

Question

The surface areas of two cubes have a ratio of 49to 81. What is the ratio of the edge lengths of the two cubes

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RuslanHeatt 1 year 2021-09-03T14:59:40+00:00 2 Answers 106 views 0

Answers ( )

    0
    2021-09-03T15:00:44+00:00

    Answer:

    Btw, this isn’t my answer someone else answered this same question, but here’s the credits to amanksingh010

    Step-by-step explanation:

    Ratio of their volumes => 343:729

    Step-by-step explanation:

    Let “a” be the side of 1st cube, and

    “b” be the side of 2nd cube.

    Given, ratio of surface areas of two cubes are 49:81

    Hence, 6a^2/6b^2 = 49/81        [Surface area of a cube=6(side)^2]

    6 will cancel out, i.e., => a^2/b^2 = 49/81

    => (a/b)^2 =  49/81

    => a/b = 7/9      [49 is square of 7 and 81 is square of 9]

    So, we got the side of 1st cube ‘a’ = 7 and,

    side of 2nd cube ‘b’ = 9

    Ratio of their volumes =>

    a^3/b^3 = 7/9           [Volume of a cube = (side)^3]

    (a/b)^3 = 7/9 => (7/9)^3 => 343/729

    Ratio => 343:729

    0
    2021-09-03T15:01:06+00:00

    Answer:it is 3 to 4

    Step-by-step explanation:

    This is correct

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