The sum of three numbers is 50. If the third number is one-third the second number and the first number exceeds the second number by 8, then

Question

The sum of three numbers is 50. If the third number is one-third the second number and the first number exceeds the second number by 8, then find the first number.

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Tryphena 5 months 2021-08-09T16:06:41+00:00 1 Answers 1 views 0

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    2021-08-09T16:07:45+00:00

    Answer:

    second number= X

    first number = X+8

    third number X/3

    sum of three numbers is 50.

    X+X+8+X/3=50

    2x+x/3=50-8

    (6x+x) / 3 =42

    7x =42*3

    X =42*3/7

    =18

    Second number=18

    third number= 18/3=6

    first number=18+8=26

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