The students at a high school collected $3,800 to buy stuffed animals to give to a children’s hospital. The students bought both stuffed be

Question

 The students at a high school collected $3,800 to buy stuffed animals to give to a children’s hospital. The students bought both stuffed bears and stuffed dogs. Each bear cost $7, and each dog cost $8. The students bought a total of 500 stuffed animals and spent all the money. How many stuffed dogs did the students buy? A. 200 B. 205 C. 295 D. 300​

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Tài Đức 6 months 2021-07-21T16:09:37+00:00 2 Answers 5 views 0

Answers ( )

    0
    2021-07-21T16:10:50+00:00

    Answer:

    D. 300

    General Formulas and Concepts:

    Pre-Algebra

    Order of Operations: BPEMDAS

    1. Brackets
    2. Parenthesis
    3. Exponents
    4. Multiplication
    5. Division
    6. Addition
    7. Subtraction
    • Left to Right

    Equality Properties

    • Multiplication Property of Equality
    • Division Property of Equality
    • Addition Property of Equality
    • Subtraction Property of Equality

    Algebra I

    • Solving systems of equations using substitution/elimination

    Step-by-step explanation:

    Step 1: Define Variables

    Stuffed bears = b

    Stuffed dogs = d

    Step 2: Define Systems

    $7b + $8d = $3800

    b + d = 500

    Step 3: Rewrite Systems

    b + d = 500

    1. [Equality Property] Multiply everything by -7:                                                 -7b – 7d = -3500

    Step 4: Redefine Systems

    7b + 8d = 3800

    -7b – 7d = -3500

    Step 5: Solve for d

    Elimination

    1. Combine 2 equations:                                                                                      d = 300

    Step 6: Define Answer

    d = 300 means that the students bought 300 stuffed dogs.

    0
    2021-07-21T16:11:13+00:00

    Answer:

    D

    Step-by-step explanation:

    Remark

    Let the stuffed bear = x

    Let the stuffed dog = y

    Equations

    x + y = 500                   (1)

    7x + 8y = 3800               (2)

    Solution

    There are two ways you could do this. You can use substitution or you could use multiplying equation 1 by either 7 or 8 to get rid of the x or y.

    Multiply (1) by 7

    7x + 7y = 3500             (3)       Write equation (2) below (3) and subtract

    7x + 8y = 3800                        Subtract

        -y = – 300                            Multiply by – 1

         y = 300

    Use the result for y to get x using equation 1

    x + y = 500

    x + 300 = 500                         Subtract 300

    x = 500 – 300

    x = 200

    Stuffed bears = 200

    Stuffed dogs   = 300

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