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## The students at a high school collected $3,800 to buy stuffed animals to give to a children’s hospital. The students bought both stuffed be

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The students at a high school collected $3,800 to buy stuffed animals to give to a children’s hospital. The students bought both stuffed bears and stuffed dogs. Each bear cost $7, and each dog cost $8. The students bought a total of 500 stuffed animals and spent all the money. How many stuffed dogs did the students buy? A. 200 B. 205 C. 295 D. 300

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Mathematics
6 months
2021-07-21T16:09:37+00:00
2021-07-21T16:09:37+00:00 2 Answers
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## Answers ( )

Answer:D. 300

General Formulas and Concepts:Pre-AlgebraOrder of Operations:

BPEMDAS

Equality Properties

Algebra IStep-by-step explanation:Step 1: Define VariablesStuffed bears =

bStuffed dogs =

dStep 2: Define Systems$7b + $8d = $3800

b + d = 500

Step 3: Rewrite Systemsb + d = 500

Step 4: Redefine Systems7b + 8d = 3800

-7b – 7d = -3500

Step 5: Solve fordEliminationStep 6: Define Answerd = 300 means that the students bought 300 stuffed dogs.

Answer:D

Step-by-step explanation:RemarkLet the stuffed bear = x

Let the stuffed dog = y

Equationsx + y = 500 (1)

7x + 8y = 3800 (2)

SolutionThere are two ways you could do this. You can use substitution or you could use multiplying equation 1 by either 7 or 8 to get rid of the x or y.

Multiply (1) by 7

7x + 7y = 3500 (3) Write equation (2) below (3) and subtract

7x + 8y = 3800Subtract-y = – 300 Multiply by – 1

y = 300

Use the result for y to get x using equation 1

x + y = 500

x + 300 = 500 Subtract 300

x = 500 – 300

x = 200

Stuffed bears = 200

Stuffed dogs = 300