The spaceship Intergalactic landed on the surface of the uninhabited Pink Planet, which orbits a rather average star in the distant Garbanzo

Question

The spaceship Intergalactic landed on the surface of the uninhabited Pink Planet, which orbits a rather average star in the distant Garbanzo Galaxy. A scouting party sets out to explore. The party’s leader–a physicist, naturally–immediately makes a determination of the acceleration due to gravity on the Pink Planet’s surface by means of a simple pendulum of length 1.44 m. She sets the pendulum swinging, and her collaborators carefully count 1.10×102 complete cycles of oscillation during 2.00×102 s. What is the result

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Sapo 3 months 2021-08-04T19:18:45+00:00 1 Answers 11 views 0

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    2021-08-04T19:20:27+00:00

    Answer:

    18808.7 m/s^2

    Explanation:

    Given

    Length of the pendulum L = 1.44 m

    Number of complete cycles of oscillation n = 1.10 x 10^2

    total time of oscillation t = 2.00 x 10^2 s

    The period of the T = n/t

    T = (1.10 x 10^2)/(2.00 x 10^2) = 0.55 ^-s

    The period of a pendulum is gotten as

    T = 2\pi \sqrt{\frac{L}{g} }

    where g is the acceleration due to gravity

    substituting values, we have

    0.55 = 2\pi \sqrt{\frac{1.44}{g} }

    0.0875 = \sqrt{\frac{1.44}{g} }

    squaring both sides of the equation, we have

    7.656 x 10^-3 = 144/g

    g = 144/(7.656 x 10^-3) = 18808.7 m/s^2

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