The sound level produced by one singer is 70.8 dB. What would be the sound level produced by a chorus of 37 such singers (all singing at the

Question

The sound level produced by one singer is 70.8 dB. What would be the sound level produced by a chorus of 37 such singers (all singing at the same intensity at approximately the same distance as the original singer)

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Xavia 2 months 2021-07-31T14:32:49+00:00 2 Answers 3 views 0

Answers ( )

    0
    2021-07-31T14:34:43+00:00

    Answer:

    86.48 dB . Ans

    Explanation:

    Sound level by one singer = 70.8 dB

    = 7.08 B

    If I be its intensity in terms of watt/m²

    log ( I / 10⁻¹² ) = 7.08 ( given )

    I / 10⁻¹²  = 10⁷°⁰⁸

    I = 10⁻¹² x 10⁷°⁰⁸

    = 10⁻⁴°⁹²

    = .000012022 W / m²

    intensity by 37 singers

    = 37 x .000012022 W /m²

    = .0004448378

    = 4448.378 x 10⁻⁷

    intensity level

    = log I / 10⁻¹² B

    = log 4448.378 x 10⁻⁷ / 10⁻¹²

    = log 444837800 B

    log 4448378 + 2 B

    = 6.6482 +2 B

    8.6482 B

    intensity level = 8.6482 B

    = 86.48 dB . Ans

    0
    2021-07-31T14:34:48+00:00

    Answer:

    86.48 dB

    Explanation:

    86.48 dB

    Explanation:

    sound level intensity, β = 70.8 dB  

    Io = 10^-12 W/m²

    Let the intensity if I at the level of 70.8 dB  

    Use the formula  

     

     

    7.08 = log I + 12

    log I = – 4.92  

    I = 1.2 x 10^-5 W/m²

    There are 37 singers, so the total intensity is I’.  

    I’ = 37 x I  

    I’ = 37 x 1.2 x 10^-5 = 4.45 x 10^-4 W/m²

    Let the sound intensity is β’ in decibels.  

    Use the formula  

     

     

    β’ = 86.48 dB

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