The solubility of a gas is 2.0 g/L at 50.0 kPa of pres- sure. How much gas will dissolve in 1 L at a pressure of 10.0 kPa?

Question

The solubility of a gas is 2.0 g/L at 50.0 kPa of pres-
sure. How much gas will dissolve in 1 L at a pressure
of 10.0 kPa?
our of

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Yến Oanh 1 month 2021-08-02T18:54:47+00:00 1 Answers 9 views 0

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    2021-08-02T18:55:47+00:00

    Answer:

    That means, under 10.0kPa of pressure, 0.4g of gas can be dissolved in 1L

    Explanation:

    Based on Henry’s law, the solubility of the gas is directly proportional to the pressure. The equation is:

    P1S2 = P2S1

    Where P is pressure and S solubility of 1, initial state and 2, final state of the gas.

    Replacing:

    P1 = 50.0kPa

    S1 = 2.0g/L

    P2 = 10.0kPa

    S2 = ??

    50.0kPa*S2 = 10.0kPa*2.0g/L

    S2 = 0.4g/L

    That means, under 10.0kPa of pressure, 0.4g of gas can be dissolved in 1L

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )