The smooth 2-kg collar is released at A and moves to the right by 0.8 m (reaching position C). The spring has an unstrected length of 0.3 m.

Question

The smooth 2-kg collar is released at A and moves to the right by 0.8 m (reaching position C). The spring has an unstrected length of 0.3 m. What is the work done by the spring on the collar from A to C?

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RI SƠ 4 years 2021-08-24T12:09:20+00:00 1 Answers 119 views 0

Answers ( )

  1. nguyetanh
    -2
    2021-08-24T12:10:39+00:00
    Reply

    Answer:

    4.9 J

    Explanation:

    From hook’s law,

    The work done in stretching a spring is given as,

    E = 1/2F×e……………….. Equation 1

    Where E= Wok done, F = force on the spring, e = extension.

    Note: from the question, The force on the spring is the weight of the collar on the spring, Therefore,

    F = W.

    Then,

    E = 1/2W×e…………….. Equation 2

    Given: W = mg = 2×9.8 = 19.6 N, e = 0.8-0.3 = 0.5 m

    Substitute into equation 2

    E = 1/2(19.6)(0.5)

    E = 4.9 J.

    Hence the work done by the collar = 4.9 J

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