The side length of an isosceles right triangle is 7x + 3 feet. (both base and height are 7x + 3 feet). then written in standard

Question

The side length of an isosceles right triangle is 7x + 3 feet. (both base and height are 7x + 3 feet).

then written in standard form, what is the area of the triangle? (area of triangle = 1/2bh)

What is the area of the triangle in cubic feet when x = 11?

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Ngọc Diệp 2 weeks 2021-08-29T19:19:44+00:00 1 Answers 0 views 0

Answers ( )

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    2021-08-29T19:21:10+00:00

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    Answer:

    • area: 49/2x^2 +21x +9/2
    • for x=11: 3200 ft^2

    Step-by-step explanation:

    The area is given by the formula in the problem statement:

      A = 1/2bh

      A = 1/2(7x +3)(7x +3) = 1/2(49x^2 +42x +9)

    The area is (49/2)x^2 +21x +9/2 . . . square feet.

    __

    When x=11, the area is …

      A = (1/2)(7·11 +3)^2 = 1/2(80^2) = 3200 . . . . square feet

    _____

    Comment on the problem statement

    Area is measured in square feet, not cubic feet.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )