the shorter side of a rectangle is 60% of the longer side and the perimeter of the rectangle is 96 inches. find the side lengths

Question

the shorter side of a rectangle is 60% of the longer side and the perimeter of the rectangle is 96 inches. find the side lengths

in progress 0
Thu Giang 6 months 2021-07-24T19:05:30+00:00 1 Answers 3 views 0

Answers ( )

    0
    2021-07-24T19:06:49+00:00

    Answer:

    Length of the rectangle:

    x =  \frac{4800}{106}  =  \frac{2400}{53}

    Breadth of the rectangle:

    60\%(x) =  \frac{60}{100}  \times  \frac{4800}{106}    \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  =60 \times  \frac{48}{106} \\  =  \frac{2880}{106}

    Step-by-step explanation:

    Longer side of the rectangle(length) = x

    Shorter side of the rectangle(breadth) = (60%)x

    Perimeter of the rectangle = 2(l+b) = 96 inches

    Hence,

    96 = 2(x + 60\%(x))

    96 = 2(x +  \frac{6}{100 } x)

    96 = 2( \frac{100}{1 00} x +  \frac{6}{100} x)

    96 = 2( \frac{106}{100} x)

    96 =  \frac{106}{50} x

    96 \div  \frac{106}{50}  = x

    96 \times  \frac{50}{106}  = x

     \frac{4800}{106}  = x

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )