The second hand on a watch has a length of 4.50 mm and makes one revolution in 60.00 s. What is the speed of the end of the second hand as i

Question

The second hand on a watch has a length of 4.50 mm and makes one revolution in 60.00 s. What is the speed of the end of the second hand as it moves in uniform circular motion

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Jezebel 4 years 2021-08-02T22:50:46+00:00 2 Answers 14 views 0

Answers ( )

  1. nguyetanh
    0
    2021-08-02T22:52:31+00:00
    Reply

    Answer:

    0.00015\pi m/s 0r 0.0004.71m/s

    Explanation:

    The speed v can be obtained through the following relationships;

    v=\omega l.................(1)

    where \omega is its angular speed and l is the length which is also equivalent to the amplitude of motion.

    Also;

    \omega=\frac{2\pi}{T}..............(2)

    where T is the period of motion which is the time it takes for the second hand to make one complete revolution.

    Substituting equation (2) into equation (1), we obtain the following;

    v=\frac{2\pi l}{T}..............(3)

    Given;

    l=4.5mm=0.0045m\\T=60.00s\\hence\\v=\frac{2\pi *0.0045}{60}..............(2)\\v=0.00015\pi m/s

    Taking \pi=3.142

    v=0.00015*3.142

    v=0,0004.71m/s

  2. Euphemia
    0
    2021-08-02T22:52:36+00:00
    Reply

    Answer:

    4.71×10⁻⁴ m/s

    Explanation:

    From the question,

    V = ωr……………. Equation 1

    Where V = speed of the second hand, ω = angular velocity of the second hand, r = radius of the second hand of the clock

    But,

    ω = 2π/T………………………….. Equation 2

    Where T = Period, π = constant

    Substitute equation 2 into equation 1

    V = 2πr/T………………….. Equation 3

    Given: r = 4.5 mm = 0.0045 m, T = 60 s

    Constant: π = 3.14

    Substitute into equation 3

    V = 2×3.14×0.0045/60

    V = 4.71×10⁻⁴ m/s

    Hence the speed of the second hand of the clock = 4.71×10⁻⁴ m/s

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