The robot HooRU is lost in space, floating around aimlessly, and radiates heat into the depths of the cosmos at the rate of 10.3 W. HooRU’s

Question

The robot HooRU is lost in space, floating around aimlessly, and radiates heat into the depths of the cosmos at the rate of 10.3 W. HooRU’s surface area is 1.77 m2 and the emissivity of its surface is 0.235. Ignoring the radiation that HooRU absorbs from the cold universe, what is HooRU’s temperature T?

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Delwyn 6 months 2021-07-13T18:34:01+00:00 1 Answers 3 views 0

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    2021-07-13T18:35:26+00:00

    Answer:

    Explanation:

    We shall use the stefan’s law to solve the problem .

    E = eA σ T⁴

    E is heat radiated per second , e is emissivity , A is area , σ is stefan’s constant and T is temperature of hot surface.

    Substituting the given values,

    10.3 = .235 x 1.77 x 5.67 x 10⁻⁸ T⁴

    T⁴ = 4.367 x 10⁸

    1.4456 x 10²

    = 144.56 K

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