The reaction is run at two temperatures where temperature 1 is lower than temperature 2. Which relationship is correct for either rate const

Question

The reaction is run at two temperatures where temperature 1 is lower than temperature 2. Which relationship is correct for either rate constant (k1 or k2) or activation energy (Ea,1 and Ea,2)

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2 months 2021-08-01T02:30:11+00:00 1 Answers 7 views 0

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    2021-08-01T02:31:54+00:00

    Answer:

    The answer is “K_1 < K_2

    Explanation:

    In the given question, the value of the K=Ae^{-\frac{Ea}{RT}} and the T_1 <T_2is the rate value which is the constant that is  K_2>K_1. As per the temperature value when its increase rate is constantly increasing. E_a is activation energy it is not dependent on the temperature that why the answer is K_1 < K_2.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )