The radioisotope radon-222 has a half-life of 3.8 days. How much of a 73.9-g sample of radon- (3 222 would be left after approximately 23 da

Question

The radioisotope radon-222 has a half-life of 3.8 days. How much of a 73.9-g sample of radon- (3 222 would be left after approximately 23 days?​

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Khải Quang 6 months 2021-07-23T15:11:44+00:00 1 Answers 10 views 0

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    2021-07-23T15:13:19+00:00

    Answer:

    1.115 g

    Explanation:

    Applying,

    R = R’2^{n/t}………………. Equation 1

    Where R = original sample of radon-222, R’ = sample of radon-222 left after decay, n = Total time, t = half-life.

    make R’ the subject of the equation

    R’ = R/(2^{n/t})…………… Equation 2

    From the question,

    Given: R = 73.9 g, n = 23 days, t = 3.8 days.

    Substitute these values into equation 2

    R’ = 73.9/(2^{23/3.8})

    R’ = 73.9/2^{6.05}

    R’ = 1.115 g

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