The product of the least and greatest of three consecutive negative odd integers is 221. Find the three integers.

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The product of the least and greatest of three consecutive negative odd integers is 221. Find the three integers.

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Thái Dương 3 months 2021-08-15T04:53:52+00:00 1 Answers 11 views 0

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    2021-08-15T04:55:41+00:00

    Answer:

    Step-by-step explanation:

    Square Root of 225 is 15 (with -15 also it would work but let’s stick to positive root)

    Now, the 1st Odd Number is 15 -2 = 13 and the 3rd Odd Number is 15 + 2 = 17.

    The required Numbers are 13 and 17.

    This works for 3 consecutive Even Numbers also.

    Why does it work?

    Because, if we have 3 numbers to be a-2, a and a+2 (Doesn’t really matter if a is positive or negative)

    (a-2)*(a+2) = a^2 – 4

    So, you see adding 4 to the Product of the 1st Number and the 3rd Number (a^2 – 4 + 4 = a^2) gives you the square of the Middle Number, which is a^2!

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )