The pressure of a sample of helium in a 200. ml container is 2.0 atm. If the helium is compressed to a pressure of 40. atm without changing

Question

The pressure of a sample of helium in a 200. ml container is 2.0 atm. If the helium is compressed to a pressure of 40. atm without changing the temperature, what would be the new volume of the gas

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Philomena 4 years 2021-07-30T18:33:23+00:00 1 Answers 27 views 0

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  1. ngocdiep
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    2021-07-30T18:34:46+00:00
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    Answer:

    V_2=10mL

    Explanation:

    Hello there!

    In this case, according to the given information, it will be possible for us to solve this problem by using the Boyle’s law as an inversely proportional relationship between pressure and volume:

    P_2V_2=P_1V_1

    In such a way, we solve for the final volume, V2, and plug in the initial volume and pressure and final pressure to obtain:

    V_2=\frac{P_1V_1}{P_2} \\\\V_2=\frac{2.0atm*200.mL}{40.atm}\\\\V_2=10mL

    Regards!

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