The pressure exerted by a phonograph needle on a record is surprisingly large, due to the very small width of the needle. show answer Incorr

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The pressure exerted by a phonograph needle on a record is surprisingly large, due to the very small width of the needle. show answer Incorrect Answer If the equivalent of 0.95 g is supported by a needle, the tip of which is a circle 0.205 mm in radius, what pressure is exerted on the record, in pascals

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MichaelMet 6 months 2021-08-02T21:05:24+00:00 1 Answers 10 views 0

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    2021-08-02T21:06:56+00:00

    Answer:

    Explanation:

    Given that,

    Mass support is

    M = 0.95g= 0.95/1000 = 0.00095kg

    Radius of circle R = 0.205mm

    r = 0.205/1000 = 0.000205m

    Then, area of the circle can be determined using

    A = πr²

    A = π × 0.000205²

    A = 1.32 × 10^-7 m²

    From pressure definitions

    Pressure = Force / Area

    The force is perpendicular to the area

    Force = weight = mg

    F = mg = 0.00095 × 9.8

    F = 9.31 × 10^-3 N

    Then,

    Pressure = Force / Area

    P = F/A

    P = 9.31 × 10^-3 / 1.32 × 10^-7

    P = 70,530.30 N/m²

    Since 1 pascal = 1 N/m²

    Then,

    P = 70,530.30 Pascals

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