The power rating of a light bulb (such as a 100-W bulb) is the power it dissipates when connected across a 120-V potential difference. Part

Question

The power rating of a light bulb (such as a 100-W bulb) is the power it dissipates when connected across a 120-V potential difference. Part A What is the resistance of a 150 W bulb? R = nothing Ω Request Answer Part B How much current does the 150 W bulb draw in normal use?

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Calantha 2 days 2021-07-22T19:24:02+00:00 1 Answers 2 views 0

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    2021-07-22T19:25:29+00:00

    To solve this problem we will apply the concepts related to the calculation of power, from the two electrical forms:

    P = VI

    P = \frac{V^2}{R}

    Here,

    V = Voltage

    I = Current

    R= Resistance

    P = Power

    PART A)

    R = \frac{V^2}{P}

    Replacing,

    R = \frac{(120V)^2}{150W}

    R = 96\Omega

    Resistance of bulb is 96\Omega

    PART B)

    I = \frac{P}{V}

    I = \frac{150W}{120V}

    I = 1.25A

    The bulb will draw 1.25A current

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