The poisonous gas hydrogen sulfide, H2S, can be neutralized with a base such as sodium hydroxide, NaOH. The unbalanced equation for th

Question

The poisonous gas hydrogen sulfide, H2S, can be neutralized with a base such as sodium hydroxide,
NaOH. The unbalanced equation for this reaction follows:
NaOH(aq) + H25(e) → Na2S(aq) + H2O(1)
A student who was asked to balance this equation wrote the following:
Na2OH(aq) + H2S(g) → Na2S(aq) + H2O(
Is this equation balanced? Is it correct? Explain why or why not, and supply the correct balanced
equation if necessary.

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niczorrrr 6 months 2021-07-12T10:33:04+00:00 1 Answers 6 views 0

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    2021-07-12T10:34:12+00:00

    Answer:

    It’s not correct. For balancing, we need to put the coefficients in the molecule, not in the athom. Because if you do this, you’re creating another molecule, instead of a balacing, for which the reaction may not happen – but anyway, it would be another reaction.

    The correct balacing is:

    2NaOH + 1H2S → 1Na2S + 2H2O

    Explanation:

    Look: Na2OH does not even exist. OH has only one free link, so he can’t – in normal conditions – make another one with any athom. That’s why we should write 2NaOH instead of Na2OH. The first means “2 mols of NaOH”.

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