The point (-6, 4) lies on a straight line that has a gradient of -2. What is the equation of this line?

Question

The point (-6, 4) lies on a straight line that has a gradient of -2. What is the
equation of this line?

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Philomena 2 months 2021-07-22T22:13:35+00:00 1 Answers 5 views 0

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    2021-07-22T22:14:50+00:00

    Given:

    Point on straight line = (-6,4)

    Gradient = -2

    To find:

    The equation of the line.

    Solution:

    Point-slope form: If a line passes through the point (x_1,y_1) with slope m, then the equation of the line is

    y-y_1=m(x-x_1)

    The line passes through the point (-6,4) with slope -2. So, the equation of the line is:

    y-4=-2(x-(-6))

    y-4=-2(x+6)

    y-4=-2x-12

    Adding 4 on both sides, we get

    y-4+4=-2x-12+4

    y=-2x-8

    Therefore, the equation of the line is y=-2x-8.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )