The outer surface of a spacecraft in space has an emissivity of 0.44 and a solar absorptivity of 0.3. If solar radiation is incident on the

Question

The outer surface of a spacecraft in space has an emissivity of 0.44 and a solar absorptivity of 0.3. If solar radiation is incident on the spacecraft at a rate of 950 W/m2, determine the surface temperature of the spacecraft when the radiation emitted equals the solar energy absorbed.

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Khải Quang 2 weeks 2021-07-16T07:23:47+00:00 1 Answers 0 views 0

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    2021-07-16T07:25:11+00:00

    Answer:

    T=326.928K

    Explanation:

    From the question we are told that:

    Emissivity e=0.44

    Absorptivity \alpha =0.3

    Rate of solar Radiation R=0.3

    Generally the equation for Surface absorbed energy is mathematically given by

     E=\alpha R

     E=0.3*950

     E=285W/m^2

    Generally the equation for Emitted Radiation is mathematically given by

     \mu=e(\sigmaT^4)

    Where

    T=Temperature

     \sigma=5.67*10^8Wm^{-2}K_{-4}

    Therefore

     \alpha*E=e \sigma T^4

     0.3*(950)=0.44(5.67*10^-8)T^4

     T=326.928K

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