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The only force acting on a 3.0 kg canister that is moving in an xy plane has a magnitude of 5.0 N. The canister initially has a velocity of
Question
The only force acting on a 3.0 kg canister that is moving in an xy plane has a magnitude of 5.0 N. The canister initially has a velocity of 3.6 m/s in the positive x direction, and some time later has a velocity of 7.0 m/s in the positive y direction. How much work is done on the canister by the 5.0 N force during this time
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Physics
4 years
2021-09-02T02:45:15+00:00
2021-09-02T02:45:15+00:00 2 Answers
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Answers ( )
Explanation:
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Answer:
The work done on the canister by the 5.0 N force during this time is
54.06 Joules.
Explanation:
Let the initial kinetic energy of the canister be
KE₁ =
=
= 19.44 J in the x direction
Let the the final kinetic energy of the canister be
KE₂ =
=
= 73.5 J in the y direction
Therefore from the Newton’s first law of motion, the effect of the force is the change of momentum and the difference in energy between the initial and the final
= 73.5 J – 19.44 J = 54.06 J