The meter was originally defined so that the period of a meter-long simple pendulum would be exactly 2.00 second. (Was your measured value c

Question

The meter was originally defined so that the period of a meter-long simple pendulum would be exactly 2.00 second. (Was your measured value close to this?) Given the relationship, T^2 alpha L (T^2 is proportional to L) what would be the length of a simple pendulum, in centimeters, with a period of exactly one second?

in progress 0
Nguyệt Ánh 2 months 2021-07-30T09:47:38+00:00 1 Answers 1 views 0

Answers ( )

    0
    2021-07-30T09:49:18+00:00

    Explanation:

    Given that,

    Initial length of simple pendulum, L_1=1\ m

    Initial time period, T_1=2\ s

    We need to find the length of the simple pendulum when the period is exactly 1 second.

    T_2=1\ s

    We know that the time period of simple pendulum is given by :

    T=2\pi \sqrt{\dfrac{L}{g}} \\\\T\propto \sqrt{L} \\\\\dfrac{T_1}{T_2}=\dfrac{L_1}{L_2}

    Put all values and find L₂

    \dfrac{T_1}{T_2}=\sqrt{\dfrac{L_1}{L_2}}\\\\L_2=\dfrac{T_2^2L_1}{T_1^2}\\\\L_2=\dfrac{1^2\times 100\ cm}{2^2\ s}\\\\L_2=25\ cm

    So, the length of the pendulum with a period of exactly one second is 25 cm.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )