The measure of ∠2 is twelve less than five times the measure of ∠1. If ∠1 and ∠2 form a linear pair, find m∠2.

Question

The measure of ∠2 is twelve less than five times the measure of ∠1. If ∠1 and ∠2 form a linear pair, find m∠2.

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Thành Đạt 4 years 2021-08-22T07:00:23+00:00 1 Answers 6 views 0

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  1. Eirian
    0
    2021-08-22T07:02:18+00:00
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    Given:

    The measure of ∠2 is twelve less than five times the measure of ∠1.

    ∠1 and ∠2 form a linear pair.

    To find:

    The measure of ∠2.

    Solution:

    Let measure of ∠1 be x.

    The measure of ∠2 is twelve less than five times the measure of ∠1.

    m\angle 2=(5(m\angle 1)-12)^\circ

    m\angle 2=(5x-12)^\circ

    ∠1 and ∠2 form a linear pair. So,

    m\angle 1+m\angle 2=180^\circ

    x^\circ+(5x-12)^\circ=180^\circ

    6x-12=180

    6x=180+12

    6x=192

    Divide both sides by 6.

    x=32

    Now,

    m\angle 2=(5(32)-12)^\circ

    m\angle 2=(160-12)^\circ

    m\angle 2=148^\circ

    Therefore, the measure of angle 2 is 148 degrees.

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