The magnetic field produced by the solenoid in a magnetic resonance imaging (MRI) system designed for measurements on whole human bodies has

Question

The magnetic field produced by the solenoid in a magnetic resonance imaging (MRI) system designed for measurements on whole human bodies has a field strength of 7.0 T, and the current in the solenoid is 2.0 \times 10^{2} A. What is the number of turns per meter of length of the solenoid

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Diễm Thu 3 years 2021-08-22T13:42:08+00:00 2 Answers 10 views 0

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    0
    2021-08-22T13:43:15+00:00

    Answer:

    Explanation:

    Magnetic field, B = 7 T

    Current , i = 2 x 100 A

    let n be the number of turns per unit length.

    The magnetic field due to a solenoid is given by

    B=\mu _{0}ni

    7=4\times 31.4\times 10^{-7}\times n\times 200

    n = 27866.24 turns per metre

    0
    2021-08-22T13:43:15+00:00

    Answer:

    Number of turns per unit length will be n=2.786\times 10^4turns/m

    Explanation:

    We have given that strength of the magnetic field produced by the solenoid B = 7 T

    Current in the solenoid i = 200 A

    Let the number of turns per unit length is n

    Magnetic field due to solenoid is given as B=\mu ni here \mu is permeability of free space n is number of turns per unit length and i is current

    So 7=4\pi \times 10^{-7}\times  n\times 200

    n=2.786\times 10^4turns/m

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