The lifespan, in years, of a certain computer is exponentially distributed. The probability that its lifespan exceeds four years is 0.30. Le

Question

The lifespan, in years, of a certain computer is exponentially distributed. The probability that its lifespan exceeds four years is 0.30. Let f(x) represent the density function of the computer’s lifespan, in years, for x>0. Determine an expression for f(x).

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Adela 2 months 2021-07-25T16:55:11+00:00 1 Answers 3 views 0

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    2021-07-25T16:56:45+00:00

    Answer:

    The correct answer is “0.300993e^{-0.300993x}“.

    Step-by-step explanation:

    According to the question,

    P(x>4)=0.3

    We know that,

    P(X > x) = e^{(-\lambda\times x)}

    ⇒     e^{(-\lambda\times 4)} = 0.3

    \lambda = 0.300993

    Now,

    f(x) = \lambda e^{-\lambda x}

    By putting the value, we get

               =0.300993e^{-0.300993x}

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