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## The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probability of a pregn

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The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probability of a pregnancy lasting days or longer. b. If the length of pregnancy is in the lowest %, then the baby is premature. Find the length that separates premature babies from those who are not premature.

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2021-07-23T11:11:17+00:00
2021-07-23T11:11:17+00:00 1 Answers
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Answer:a)The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of , in which is the mean and is the standard deviation.b)We have to find X when Z has a p-value of , and X is given by: , in which is the mean and is the standard deviation.Step-by-step explanation:Normal Probability DistributionProblems of normal distributions can be solved using the z-score formula.

In a set with mean and standard deviation , the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:Mean , standard deviation

a. Find the probability of a pregnancy lasting X days or longer.The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of , in which is the mean and is the standard deviation.

b. If the length of pregnancy is in the lowest a%, then the baby is premature. Find the length that separates premature babies from those who are not premature.We have to find X when Z has a p-value of , and X is given by: , in which is the mean and is the standard deviation.