The length of a rectangle is eight more than double the width. If the perimeter is 130 inches, find the dimensions.

Question

The length of a rectangle is eight more than double the width. If the perimeter is 130 inches, find the
dimensions.

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Trúc Chi 5 months 2021-08-15T00:44:27+00:00 1 Answers 15 views 0

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    2021-08-15T00:45:59+00:00

    Answer:

    The length is 46 inches and the width is 19 inches

    Step-by-step explanation:

    Let w represent the width.

    The length of the rectangle can be represented by 2w + 8, since it is eight more than double the width.

    Use the perimeter formula, p = 2l + 2w. Plug in 130 as the perimeter and 2w + 8 as l, then solve for w:

    p = 2l + 2w

    130 = 2(2w + 8) + 2w

    130 = 4w + 16 + 2w

    130 = 6w + 16

    114 = 6w

    19 = w

    So, the width is 19 inches. Plug in 19 as w into 2w + 8 to find the length:

    2w + 8

    2(19) + 8

    38 + 8

    = 46

    The length is 46 inches and the width is 19 inches

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