The length of a rectangle is 3 inches longer than twice its width, where w is the width of th rectangle. The area of the rectangle is

Question

The length of a rectangle is 3 inches longer than twice its width, where w is the width of th
rectangle. The area of the rectangle is 90 square inches. *

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RuslanHeatt 1 year 2021-09-03T23:34:27+00:00 2 Answers 8 views 0

Answers ( )

  1. Verity
    0
    2021-09-03T23:35:53+00:00
    Reply

    ASSUMPTION:

    Let width be x, then length be 2x + 3.

    GIVEN:

    • Area of rectangle = 90in²

    ANSWER:

    We know that,

    Area of rectangle = lw

    • x(2x + 3) = 90
    • 2x² + 3x – 90 = 0

    So, x = – 3 ± √3² – 4 × 2 × – 90/2 × 2

    • x = – 3 ± √729/4
    • x = – 3 ± 27/4
    • x = 6 (width can’t be negative)

    Then, length = 2 × 6 + 3 = 15in.

    Hence, length of rectangle is 15in and width is 6in.

  2. minhkhang
    0
    2021-09-03T23:36:21+00:00
    Reply

    Answer:

    • 6 in and 15 in

    Step-by-step explanation:

    Given:

    • l = 2w + 3
    • A = 90 in²
    • w = ?
    • l = ?

    Area formula:

    • A = lw

    Substitute values and solve for w:

    • (2w+3)w = 90
    • 2w² + 3w = 90
    • 2w² + 3w – 90 = 0
    • w = (-3 ± [tex]\sqrt{3^2 – 4*2*(-90)}[/tex])/2*2
    • w = (-3 ± √729)/4
    • w = (-3 ± 27)/4
    • w = 6 (positive root only)

    The width is 6 in, find the length:

    • l = 2*6 + 3 = 15 in

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )