The length of a rectangle field is represented by the expression 14 X minus 3X squared +2 Y. The width of the field is represented by the ex

Question

The length of a rectangle field is represented by the expression 14 X minus 3X squared +2 Y. The width of the field is represented by the expression 5X minus 7X squared plus 7Y. How much greater is the length of the field than the width?

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Mộc Miên 7 months 2021-07-23T05:38:28+00:00 1 Answers 4 views 0

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    2021-07-23T05:39:47+00:00

    Answer:

    9x+4x^2-5y

    Step-by-step explanation:

    Hi there!

    Length of the field: 14x-3x^2+2y units

    Width of the field: 5x-7x^2+7y units

    To find how much greater the length of the field is than the width, subtract the width from the length:

    14x-3x^2+2y-(5x-7x^2+7y)

    Open up the parentheses

    = 14x-3x^2+2y-5x+7x^2-7y

    Combine like terms

    = 14x-5x-3x^2+7x^2+2y-7y\\= 9x+4x^2-5y

    Therefore, the length is 9x+4x^2-5y units greater than the width.

    I hope this helps!

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