The launching catapult of the aircraft carrier gives the jet fighter a constant acceleration of 59 m/s2 from rest relative to the flight dec

Question

The launching catapult of the aircraft carrier gives the jet fighter a constant acceleration of 59 m/s2 from rest relative to the flight deck and launches the aircraft in a distance of 97 m measured along the angled takeoff ramp. If the carrier is moving at a steady 26 knots (1 knot = 1.852 km/h), determine the magnitude v of the actual velocity of the fighter when it is launched.

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Orla Orla 6 months 2021-07-25T20:56:27+00:00 1 Answers 8 views 0

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    2021-07-25T20:58:22+00:00

    Answer:

    Explanation:

    We shall find the final velocity of  aircraft with respect to aircraft carrier using the following relation.

    v² = u² + 2as

    v² = 0² + 2 x 59 x 97

    v² = 11446

    v = 107 m /s

    velocity of aircraft carrier = 1.852 x 26 = 48.152 km/h

    = 48.152 x 1000 / (60 x 60) m/s

    = 13.37 m /s

    This velocity of aircraft carrier will be added to the velocity of aircraft .

    So absolute velocity of aircraft = 107 m /s + 13.37 m/s

    = 120.37 m/s

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