The label on a candy bar says 410 Calories. For the steps and strategies involved in solving a similar problem, you may view a Video Tutor S

Question

The label on a candy bar says 410 Calories. For the steps and strategies involved in solving a similar problem, you may view a Video Tutor Solution. Part A Assuming a typical efficiency for energy use by the body, if a 60 kg person were to use the energy in this candy bar to climb stairs, how high could she go?

in progress 0
niczorrrr 2 months 2021-07-30T01:22:37+00:00 2 Answers 5 views 0

Answers ( )

    0
    2021-07-30T01:24:03+00:00

    Answer:

    h = 729.66 m

    Explanation:

    We are given;

    Energy contained in candy bar;

    Q_in = 410 calories = 410 x 4190 J =

    1,717,900 J

    Now the formula for efficiency of a human body is;

    e = work output /work input = Q_out/Q_in

    The efficiency of a human body is 0.25. Thus;

    0.25 = Q_out/Q_in

    So, Q_out = 0.25 x 1,717,900

    Q_out = 429,475 J

    This Q_out is the gravitational potential energy

    Thus, we know that the formula foe Potential energy is;

    PE = mgh

    Where m is mass, g is acceleration due to gravity and h is height.

    Thus,

    429,475 = 60 x 9.81 x h

    h = 429,475/(60 x 9.81)

    h = 729.66 m

    0
    2021-07-30T01:24:21+00:00

    Answer:

    2.9174meters.

    Explanation:

    410Calories = 1715.44 Joules (Energy).

    we have essentially calculate height at which Gravitational potential is 1715.44 Joules.

    We know that Gravitational Potential as a function of height above reference point is.

    G(h)=mgh.

    Substituting values in gives.

    1715.44 joules = 60Kg*9.8m/s^2*h

    in above solve for h and you will get.

    h = 2.917meters (units are meters by dimentional analysis ).

    That is the height a 60Kg person can reach by climbing stairs.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )