The inner circle circumference is 52 ft. the distance between the inner and the outer circle is 8ft. By how many ft is the outer circle larg

Question

The inner circle circumference is 52 ft. the distance between the inner and the outer circle is 8ft. By how many ft is the outer circle larger?

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Vân Khánh 4 years 2021-07-30T09:49:50+00:00 1 Answers 22 views 0

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  1. Giakhanh
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    2021-07-30T09:51:08+00:00
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    Answer:

    The outer circle is 16 feet larger than the inner circle (68 – 52).

    Step-by-step explanation:

    Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:

    The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).

    This implies that the outer circle is 16 feet larger than the inner circle (68 – 52).

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