The index of refraction of a clear plastic is listed as 1.89 in the book, but you measured the angle of incidence 63.5° and the angle of ref

Question

The index of refraction of a clear plastic is listed as 1.89 in the book, but you measured the angle of incidence 63.5° and the angle of refraction 32°. What index of refraction did you calculate and what is the percentage error?

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Thu Cúc 4 weeks 2021-08-19T13:01:11+00:00 1 Answers 1 views 0

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    2021-08-19T13:02:28+00:00

    Answer:

    index of refraction = 1.69

    percentage error = 10.58%

    Explanation:

    According to Snell’s law, the ratio of the sine of angle of incidence to the sine of angle of refraction is a constant for a given pair of media. The constant is known as the refractive index.

    Mathematically \frac{sin i}{sin r} = n

    i = angle of incidence measured = 63.5°

    r = angle of refraction measured = 32°

    n = refractive index

    n = \frac{sin 63.5^{0} }{sin 32^{0} } \\n = \frac{0.8949}{0.5299}\\ n = 1.69

    The index fraction calculated is approx. 1.69.

    If the index of refraction of a clear plastic as listed in the book is 1.89 and the calculated is 1.69, the percentage error will be calculated as thus;

    %error = \frac{1.89-1.69}{1.89} * 100

    %error = \frac{0.2}{1.89}*100

    %error  = \frac{20}{1.89}

    %error  = 10.58%

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