The hydrogen molecule will start to vibrate at temperatures above roughly 1000 K. At this high temperature, what is the ratio of the interna

Question

The hydrogen molecule will start to vibrate at temperatures above roughly 1000 K. At this high temperature, what is the ratio of the internal energy of hydrogen gas to the internal energy of helium gas, assuming that the number of molecules in each gas is the same. Write your answer as a number in normal form, as described in the instructions.

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Ngọc Diệp 4 years 2021-07-21T17:02:12+00:00 1 Answers 13 views 0

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  1. vankhanh
    0
    2021-07-21T17:03:39+00:00
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    Answer:

    Explanation:

    At the temperature of 1000K , hydrogen will have following degree of freedom

    translational = 3

    rotational = 2

    vibrational = 1

    Total = 6

    Internal energy = 6N  x 1 /2 k T where N is no of molecules

    E₁ = 3 N kT

    At the temperature of 1000K , helium  will have following degree of freedom

    translational = 3

    rotational = 0

    vibrational =  0

    Total = 3

    Internal energy = 3N  x 1 /2 k T where N is no of molecules

    E₂ = 3 / 2 N kT

    Ratio =  E₁ / E₂

    =  2

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