The hull of a sunken boat, laying on the seabed, is 9 m below the surface of the sea, where the sea water has an average density of 1,025 kg

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The hull of a sunken boat, laying on the seabed, is 9 m below the surface of the sea, where the sea water has an average density of 1,025 kg/m3. The hull’s surface area is 12 m2. What is the total force exerted by seawater on the hull?Required to answer. Single line text.

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  1. Answer:

    1084860 N

    Explanation:

    Applying,

    P = ρgh……………. Equation 1

    Where P = pressure, ρ = density, h = height, g = acceleration due to gravity.

    From the question,

    Given:  ρ = 1025 kg/m³, h = 9 m

    Constant: g = 9.8 m/s²

    Substitute these values into equation 1

    P = (1025)(9)(9.8)

    P = 90405 N/m²

    Also,

    P = F/A………….. Equation 2

    Where, F = Force, A = Area.

    Make F the subject of the equation

    F = PA…………… Equation 2

    Given: A = 12m²

    F = 12(90405)

    F = 1084860 N

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