The Hubble Space Telescope has a mass of 1.16*10^ 4 kg and orbits the Earth at an altitude of 5.68 * 10 ^ 5 above Earth’s surface. Relative

Question

The Hubble Space Telescope has a mass of 1.16*10^ 4 kg and orbits the Earth at an altitude of 5.68 * 10 ^ 5 above Earth’s surface. Relative to infinitydetermine the potential energy the telescope at this location. Would the formula be Ep=-Gm1m2/r or positive G since it’s relative to infinity

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Khải Quang 2 months 2021-07-31T19:33:34+00:00 1 Answers 2 views 0

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    2021-07-31T19:34:59+00:00

    Answer:

    E=8.13\times 10^{12}\ J

    Explanation:

    Given that,

    The mass of a Hubble Space Telescope, m_1=1.16\times 10^4\ kg

    It orbits the Earth at an altitude of 5.68\times 10^5\ m

    We need to find the potential energy the telescope at this location. The formula for potential energy is given by :

    E=\dfrac{Gm_1m_e}{r}

    Where

    m_e is the mass of Earth

    Put all the values,

    E=\dfrac{6.67\times 10^{-11}\times 1.16\times 10^4\times 5.97\times 10^{24}}{5.68\times 10^5}\\\\E=8.13\times 10^{12}\ J

    So, the potential energy of the telescope is 8.13\times 10^{12}\ J.

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