the heat capacity of 0.125Kg of water is measured to be 523j/k at a room temperature.Hence, calculate the heat capacity of water (a) p

Question

the heat capacity of 0.125Kg of water is measured to be 523j/k at a room temperature.Hence, calculate the heat capacity of water
(a) per unit mass
(b) per unit volume​

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Acacia 4 years 2021-08-31T09:15:44+00:00 1 Answers 44 views 0

Answers ( )

  1. Cherry
    0
    2021-08-31T09:17:07+00:00
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    Answer:

    A. 4148 J/K/Kg

    B. 4148 J/K/L

    Explanation:

    A. Heat capacity per unit mass is known as the specific heat capacity, c.

    C = Heat capacity/mass(kg)

    C = (523 J/K) / 0.125 Kg = 4148 J/K/Kg

    B. Volume of water = mass/density

    Density of water = 1 Kg/L

    Volume of water = 0.125 Kg/ 1Kg/L

    Volume of water = 0.125 L

    Heat capacity per unit volume = (523 J/K) / 0.125 L

    Heat capacity per unit volume = 4148 J/K/L

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