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The head scale of a screw gauge contains 100 divisions and it’s pitch is 1mm. what is the least count of the screw gauge
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Answers ( )
Answer:
0.01 mm
Explanation:
The least count of the screw gauge = pitch/number of divisions on circular scale
Pitch = 1 mm and number of divisions = 100
Substituting the values of the variables into the equation, we have
least count of the screw gauge = pitch/number of divisions on circular scale = 1 mm/100 = 0.01 mm