The friends are ready to try a problem. A battery has an emf of 12.0 V and an internal resistance of 0.05 Ω. Its terminals are connected to

Question

The friends are ready to try a problem. A battery has an emf of 12.0 V and an internal resistance of 0.05 Ω. Its terminals are connected to a load resistance of 1.1 Ω. Find the terminal voltage of the battery. V Calculate the power delivered to the load resistor, the power delivered to the internal resistance of the battery, and the power delivered by the battery. PR = W Or = W Delivered by battery = W

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Khoii Minh 4 years 2021-09-01T03:48:42+00:00 1 Answers 31 views 0

Answers ( )

  1. thienhuong
    0
    2021-09-01T03:50:02+00:00
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    Answer:

    Terminal voltage = 11.5 V

    Power across load = 119.7 W

    Power across internal resistance = 5.4 W

    Power delivered by battery = 125.2 W

    Explanation:

    The current in the circuit is given by

    I=\dfrac{E}{R+r}

    where E is the emf of the battery, R us the load resistance and r is the internal resistance.

    I=\dfrac{12}{1.1+0.05} = 10.43 \text{ A}

    The terminal voltage is the potential difference across the load resistor.

    V = I × R = 10.43 A × 1.1 Ω = 11.5 V

    The power across any resistance is given by I^2R

    For the load resistor,

    P_L=10.43^2\times1.1 = 119.7 \text{ W}

    For the internal resistance,

    P_r=10.43^2\times0.05= 5.4\text{ W}

    The power delivered by the battery is

    P = P_L + P_r = 119.7 + 5.4 = 124.1 \text{ W}

    This could also be found by

    P = IE = 10.34\times12 = 125.2 \text{ W}

    The discrepancy in both answers is due to the approximations. The second answer is better.

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